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Proof step 3 from proof icrash-remove-refsize0-prefix (previous step)

⊦ istore ⊑ istore0 ↔ dom istore ⊆ dom istore0 ∧ (∀ n. n ∈ istore ∧ n ∈ istore0 → istore[n].indlist ⊑ istore0[n].indlist ∧ istore[n].ladrlist ⊑ istore0[n].ladrlist ∧ # istore[n].indlist = # istore[n].ladrlist ∧ # istore0[n].indlist = # istore0[n].ladrlist)

A spec-lemma