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Proof step 2 from proof notin-gstore-ginval-notin-gstore0 (
previous step
)
dom gstore0 ∪ elems nx = dom gstore ∪ ginval, n ∈ gstore0 ⊦ n ∈ ginval, n ∈ gstore
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
dom gstore0 ∪ elems nx = dom gstore ∪ ginval, n ∈ gstore0 ⊦ n ∈ gstore, n ∈ ginval
Rule argument
Additional information