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Proof step 1 from proof id-idx-fwd-0 (conclusion)

⊦ lpt0[n] = mklp(n0, n1, lpf0, n2) ∧ lpt1[n] = mklp(m0, m1, lpf1, m2) ∧ n < # lpt0 ∧ id-idx(lpt0, lpt1) → n0 = m0 ∧ n1 = m1 ∧ lpf0 = lpf1

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information