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Proof step 1 from proof id-idx-ls0 (conclusion)
⊦ id-idx(lpt0, lpt1) → ¬ # lpt0 < # lpt1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
# lpt0 < # lpt1, id-idx(lpt0, lpt1) ⊦
Rule argument
Additional information