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Proof step 12 from proof dom-max-in (previous step)

(m < (dom st0).max ⊃ (dom st0).max;m) < n, n ∈ st0[m, d], (∃ n. (dom st0).max < n ∧ n ∈ st0) → st0 = ∅ ⊦ st0 = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information