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Proof step 3 from proof is-aligned-pagesize-imp-2headersize (previous step)

is-aligned(n, EB_PAGE_SIZE) ⊦ is-aligned(n, 2 * NODE_HEADER_SIZE)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
m ≠ 0 ⊦ is-aligned(n, m) ↔ (∃ n0. n = n0 * m)
Proof step 5:
∃ n0. n = n0 * EB_PAGE_SIZE ⊦ EB_PAGE_SIZE = 0, is-aligned(n, 2 * NODE_HEADER_SIZE)

Rule argument

spec: align name: is-aligned-elim seq: m ≠ 0 ⊦ is-aligned(n, m) ↔ (∃ n0. n = n0 * m) subst: [m, n] → [EB_PAGE_SIZE, n] flags: <all paths>

Additional information

Used simplifier rules: ⊦ EB_PAGE_SIZE ≠ 0; (s) Used terms: EB_PAGE_SIZE, n