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Proof step 12 from proof leb-size-aligned-2-node-header (previous step)

LEB_SIZE % EB_PAGE_SIZE = 0, EB_PAGE_SIZE = m0 * 2 * NODE_HEADER_SIZE + n0, n0 = 0, n0 < 2 * NODE_HEADER_SIZE ⊦ LEB_SIZE % (2 * NODE_HEADER_SIZE) = 0, 2 * NODE_HEADER_SIZE = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
LEB_SIZE % EB_PAGE_SIZE = 0, EB_PAGE_SIZE = m0 * 2 * NODE_HEADER_SIZE ⊦ LEB_SIZE % (2 * NODE_HEADER_SIZE) = 0

Rule argument

Additional information

Used simplifier rules: nodeheader-notzero: ⊦ NODE_HEADER_SIZE ≠ 0;% ⊦ 0 < m ↔ m ≠ 0; (s)%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ 2 * m = 0 ↔ m = 0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)