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Proof step 16 from proof leb-size-aligned-2-node-header (previous step)

EB_PAGE_SIZE = m0 * 2 * NODE_HEADER_SIZE, LEB_SIZE = m1 * EB_PAGE_SIZE, LEB_SIZE = m2 * 2 * NODE_HEADER_SIZE + n0, n0 < 2 * NODE_HEADER_SIZE ⊦ 2 * NODE_HEADER_SIZE = 0, n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
EB_PAGE_SIZE = m0 * 2 * NODE_HEADER_SIZE, LEB_SIZE = m1 * EB_PAGE_SIZE, LEB_SIZE = m2 * 2 * NODE_HEADER_SIZE + n0, n0 < 2 * NODE_HEADER_SIZE ⊦ n0 = 0

Rule argument

Additional information

Used simplifier rules: nodeheader-notzero: ⊦ NODE_HEADER_SIZE ≠ 0;%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ 2 * m = 0 ↔ m = 0; (s)