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Proof step 49 from proof inv-allocate-ind (previous step)

# lpt = # avol0, # lpt0 = # avol0, lpt[n0] = mklp(0, m1, LP_FREE, m2), keyset(gch) = gc-heap(lpt, log0), n0 < # avol0, awbuf-inv(avol0, bleb), awbuf-inv(avol0[n0, mapped(mkbuf(0))], bleb), bin-heap-inv(gch, lpt), buf-ro-rw-mode(false, bleb, lpt, avol0), bufs-log-only(bleb, log0, lpt), freelist-cons(lpt, n0 ' + nx0), log-group-block(log0, lpt), lpt-free-unref(lpt0), lpt-free-unref(lpt), lpt-leb-size(lpt0), lpt-leb-size(lpt), lpt-ram-flash(lpt, lpt0, log0), synced(avol0) ⊦ bleb = nobuffer, buffered(n0) = bleb, is-aligned(# avol0[n0, mapped(mkbuf(0))][bleb.leb].data, EB_PAGE_SIZE)

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

spec: bufleb name: elim seq: ⊦ bleb ≠ nobuffer → (m = bleb.leb ↔ bleb = buffered(m)) subst: [bleb, m] → [bleb, m]

Additional information

Used simplifier rules: ⊦ buffered(m) = buffered(m0) ↔ m = m0; (s)% ⊦ nobuffer ≠ buffered(m); (s)% ⊦ m ≠ n → avol[n, aleb][m] = avol[m]; (s)%⊦ awbuf-inv(avol, buffered(n)) ∧ synced(avol) → is-aligned(# avol[n].data, EB_PAGE_SIZE); (s)% ⊦ bleb ≠ nobuffer → (m = bleb.leb ↔ bleb = buffered(m)); (elim) Used terms: bleb, m