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Proof step 28 from proof inv-read-ind (previous step)

# lpt = # avol, # lpt0 = # avol, LEB_SIZE = n0 + # buf1, avol[m4] = mapped(buf1), m4 < # avol, abs-node(subarray(buf1, m3, m2), ind), awbuf-inv(avol, bleb), buf-ro-rw-mode(isbuf, bleb, lpt0, avol), bufs-log-only(bleb, log0, lpt0), lpt-free-unref(lpt), lpt-leb-size(lpt), lpt-ram-flash(lpt0, lpt, log0), m3 + m2 ≤ # buf1, m3 + m2 ≤ LEB_SIZE, # buf1 ≤ LEB_SIZE ⊦ ∀ ind0, err0. abs-node(subarray(avol[m4].data, m3, 2 * NODE_HEADER_SIZE + ind0.alignedsize), ind0) ∧ m2 = 2 * NODE_HEADER_SIZE + ind0.alignedsize → err0 = ESUCCESS → ind = ind0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ abs-node(buf, ind) → (abs-node(buf, ind0) ↔ ind = ind0); (s)% ⊦ mapped(buf).data = buf; (s)%let: ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward) from specification nat