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Proof step 34 from proof inv-read-ind (previous step)

# lpt = # avol, # lpt0 = # avol, avol[m4] = mapped(buf1), buf = mkbuf(m2), err = err0, n = m2, m4 < # avol, abs-node(subarray(buf1, m3, m2), ind), awbuf-inv(avol, bleb), buf-ro-rw-mode(isbuf, bleb, lpt0, avol), bufs-log-only(bleb, log0, lpt0), lpt-free-unref(lpt), lpt-leb-size(lpt), lpt-ram-flash(lpt0, lpt, log0), m3 + m2 ≤ # buf1, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err = ESUCCESS, ∃ buf1. # buf1 = # buf ∧ range=(buf1, n, buf, n, # buf - n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
# lpt0 = # avol, # lpt = # avol, avol[m4] = mapped(buf1), m4 < # avol, abs-node(subarray(buf1, m3, m2), ind), awbuf-inv(avol, bleb), buf-ro-rw-mode(isbuf, bleb, lpt0, avol), bufs-log-only(bleb, log0, lpt0), lpt-free-unref(lpt), lpt-leb-size(lpt), lpt-ram-flash(lpt0, lpt, log0), m3 + m2 ≤ # buf1, ⌊err0⌋ ⊦ ∃ buf. # buf = m2

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)% ⊦ range=(buf, n0, buf0, n1, 0) ↔ n0 ≤ # buf ∧ n1 ≤ # buf0; (s)% ⊦ m - m = 0; (s)% ⊦ # mkbuf(n) = n; (s)% ⊦ ⌊err⌋ → err ≠ ESUCCESS; (s)