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Proof step 138 from proof inv-sync (previous step)

# lpt0 = # avol, # lpt1 = # avol, isbuf ↔ isbuf1, lpt1[bleb1.leb] = mklp(m3, m5, lpf, m4), bleb = bleb1, ¬ isbuf1, keyset(gch) = gc-heap(lpt1, log0), log = log0, lpt = lpt0, m = m2, bleb1.isbuf?, awbuf-inv(avol, bleb1), bin-heap-inv(gch, lpt1), buf-ro-rw-mode(isbuf1, bleb1, lpt1, avol), bufs-log-only(bleb1, log0, lpt1), freelist-cons(lpt1, freelist), log-group-block(log0, lpt1), lpt-free-unref(lpt0), lpt-free-unref(lpt1), lpt-leb-size(lpt0), lpt-leb-size(lpt1), lpt-ram-flash(lpt1, lpt0, log0), bleb1.isbuf? ∧ ¬ isbuf1 → bleb1.leb < # avol ∧ # avol[bleb1.leb].data ≤ LEB_SIZE ∧ avol[bleb1.leb].mapped? ∧ m5 = # avol[bleb1.leb].data ∧ lpf ≠ LP_FREE ∧ is-aligned(# avol[bleb1.leb].data, 2 * NODE_HEADER_SIZE) ⊦ bleb1.leb < # lpt1 ∧ bleb1.isbuf?

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: elim-mapped: ⊦ avol[n].mapped? ↔ (∃ buf. avol[n] = mapped(buf));% ⊦ buffered(m).isbuf?; (s)% ⊦ buffered(m).leb = m; (s)% ⊦ bleb.isbuf? ↔ (∃ n. bleb = buffered(n)); (as)