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Proof step 104 from proof prepost-cleanup-lpt (previous step)

# lpt4 = n2 + n0, # avol1 = n2 + n0, # lpt3 = n2 + n0, lpt3[n0] = mklp(0, m1, lpf, m2), bleb = nobuffer, keyset(gch0) = gc-heap(lpt4, []), keyset(gch) = gc-heap(cleanup-lpt(lpt4, n0), []), lpt = lpt0, m0 = n0, avol-cleanup-lpt-unchanged(avol1, avol, lpt4), awbuf-inv(avol1, nobuffer), awbuf-inv(avol, nobuffer), bin-heap-inv(gch0, lpt4), bin-heap-inv(gch, lpt3), freelist-cons(lpt4, freelist0), freelist-cons(cleanup-lpt(lpt4, n0), freelist), id-idx(cleanup-lpt(lpt4, n0), lpt3), synced(avol1), synced(avol) ⊦ ⟪abort; n1 := n0 + 1⟫ ( n1 ≤ # lpt4 ∧ id-idx(cleanup-lpt(lpt4, n1), lpt3[n0, mklp(0, 0, LP_FREE, m2)]) ∧ awbuf-inv(avol, nobuffer) ∧ avol-cleanup-lpt-unchanged(avol1, avol, lpt4) ∧ freelist-cons(cleanup-lpt(lpt4, n1), freelist + n0 ') ∧ keyset(gch) = gc-heap(cleanup-lpt(lpt4, n1), []) ∧ # lpt4 < n2 + n1), lpf = LP_GROUP_NODES, lpf = LP_FREE, n2 = 0, synced(avol) ∧ m0 < # avol ∧ buffered(m0) ≠ bleb

Heuristic symbolic execution applied rule abort right

And obtained the following new goals

Rule argument

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