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Proof step 38 from proof prepost-create-freelist (previous step)

n0 < # lpt, freelist-cons(subarray(lpt, 0, n0), freelist) ⊦ lpt[n0].flags = LP_FREE, freelist-cons(subarray(lpt, 0, n0 + 1), freelist)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 39:
lpt[n0] = mklp(m, m0, lpf, m1), n0 < # lpt, freelist-cons(subarray(lpt, 0, n0), freelist) ⊦ lpf = LP_FREE, freelist-cons(subarray(lpt, 0, n0 + 1), freelist)

Rule argument

spec: lprops name: elim seq: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1) subst: [lp, m, m0, lpf, m1] → [lpt[n0], m, m0, lpf, m1]

Additional information

Used simplifier rules: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1); (elim) Used terms: lpt[n0], m, m0, lpf, m1