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Proof step 47 from proof prepost-create-freelist (previous step)

n < n0 ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist, subarray(lpt, 0, n0 + 1)[n] = mklp(m2, m3, lpf0, m4), lpt[n0] = mklp(m, m0, lpf, m1), n0 < # lpt ⊦ ¬ n0 < n ∧ lpf0 = LP_FREE ↔ n ∈ freelist, lpf = LP_FREE, dups(freelist)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 48:
n < n0 ∧ lpf1 = LP_FREE ↔ n ∈ freelist, lpt[n0] = mklp(m, m0, lpf, m1), subarray(lpt, 0, n0 + 1)[n] = mklp(m2, m3, lpf0, m4), lpt[n] = mklp(m5, m6, lpf1, m7), n0 < # lpt ⊦ ¬ n0 < n ∧ lpf0 = LP_FREE ↔ n ∈ freelist, lpf = LP_FREE, dups(freelist)

Rule argument

spec: lprops name: elim seq: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1) subst: [lp, m, m0, lpf, m1] → [lpt[n], m5, m6, lpf1, m7]

Additional information

Used simplifier rules: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1); (elim) Used terms: lpt[n], m5, m6, lpf1, m7