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Proof step 9 from proof prepost-create-freelist (previous step)

freelist0 = [], n = n0, n1 = 0, n < # lpt, freelist-cons(subarray(lpt, 0, n), freelist), n ≤ # lpt ⊦ ⟪if lpt[n].flags = LP_FREE then freelist := freelist + n; n := n + 1⟫ ((n ≤ # lpt ∧ freelist-cons(subarray(lpt, 0, n), freelist)) ∧ # lpt - n < # lpt - n0)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Proof step 10:
lpt[n].flags = LP_FREE, freelist0 = [], n = n0, n1 = 0, n < # lpt, freelist-cons(subarray(lpt, 0, n), freelist), n ≤ # lpt ⊦ ⟪freelist := freelist + n; n := n + 1⟫ ((n ≤ # lpt ∧ freelist-cons(subarray(lpt, 0, n), freelist)) ∧ # lpt - n < # lpt - n0)
Proof step 35:
freelist0 = [], n = n0, n1 = 0, n < # lpt, freelist-cons(subarray(lpt, 0, n), freelist), n ≤ # lpt ⊦ ⟪skip; n := n + 1⟫ ((n ≤ # lpt ∧ freelist-cons(subarray(lpt, 0, n), freelist)) ∧ # lpt - n < # lpt - n0), lpt[n].flags = LP_FREE
Proof step 52:
freelist0 = [], n = n0, n1 = 0, n < # lpt, freelist-cons(subarray(lpt, 0, n), freelist), n ≤ # lpt ⊦ n < # lpt

Rule argument

pos: right 1

Proof step 9 from proof prepost-create-freelist (previous step)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

Additional information