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Proof step 19 from proof prepost-encode-group-nodes (previous step)

# gndx0 = # lax, # buf0 = gndx0.flashsize, # buf1 = gndx1.flashsize, gndx1.flashsize < 2 * NODE_HEADER_SIZE + gndx1[# lax - # gndx0].alignedsize, abs-nodes(buf0, n, gndx0, lax, false) ⊦ # lax + # gndx1 = 0, gndx1 = [], # lax < # gndx0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# buf1 = gndx1.flashsize, # buf0 = gndx0.flashsize, # gndx0 = # lax, gndx1.flashsize < 2 * NODE_HEADER_SIZE + gndx1.head.alignedsize, abs-nodes(buf0, n, gndx0, lax, false) ⊦ # lax + # gndx1 = 0, gndx1 = []

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ 2 * NODE_HEADER_SIZE + n ≠ 0; (s)% ⊦ gndx ≠ [] → gndx[0] = gndx.head; (s)% ⊦ m - m = 0; (s)%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n ↔ ¬ n ≤ m; (ss)