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Proof step 7 from proof prepost-replay-lpt (previous step)

# lpt4 = # avol1, isbuf ↔ boolvar, avol0 = avol1, bleb = nobuffer, log = log1, log0 = nx, lpt = lpt3, lpt = replay-lpt(lpt4, log0, n), lpt0 = lpt1, lpt2 = lpt4, m = m1, m0 = LEB_SIZE, n = n0, n1 = 0, n < # lpt, avol-replay-lpt-unchanged(avol1, avol, lpt4, log0), awbuf-inv(avol, bleb), awbuf-inv(avol1, nobuffer), synced(avol), synced(avol1), n ≤ # lpt4 ⊦ ⟪if lpt[n].flags = LP_INDEX_NODES then lpt[n].size := m0; if lpt[n].ref-size = 0 then {lpt[n].flags := LP_FREE; lpt[n].size := 0; awbuf_unmap#(n, adr, m, log, lpt0, ns, bleb, isbuf; avol)}; n := n + 1⟫ ( ( n ≤ # lpt4 ∧ awbuf-inv(avol, bleb) ∧ bleb = nobuffer ∧ lpt = replay-lpt(lpt4, log0, n) ∧ # lpt4 = # avol1 ∧ avol-replay-lpt-unchanged(avol1, avol, lpt4, log0) ∧ synced(avol)) ∧ # lpt - n < # lpt3 - n0), lpt[n].flags = LP_FREE, n ∈ log0

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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