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Proof step 17 from proof abs-istore-cleanup-lpt (previous step)

# avol0 = # avol1, # lpt = # avol1, (m4 = 0 ∧ lpf0 ≠ LP_FREE ⊃ mklp(0, 0, LP_FREE, m6);mklp(m4, m5, lpf0, m6)) = mklp(m0, m1, lpf, m2), lpf0 = LP_INDEX_NODES ↔ n ∈ istore, istore[n] = indexblock(indx0, lax0, m3), remove-refsize0(istore)[n] = indexblock(indx, lax, m), lpt[n] = mklp(m4, m5, lpf0, m6), n < # avol1, n ∈ istore → abs-leb(avol0[n], indexblock(indx0, lax0, m3), mklp(m3, m5, lpf0, m6)) ∧ m4 = m3, ∀ n. n < # avol1 ∧ (lpt[n].ref-size ≠ 0 ∨ lpt[n].flags = LP_FREE) → avol0[n] = avol1[n], ¬(lpf = LP_INDEX_NODES ↔ n ∈ remove-refsize0(istore)) ∨ ¬(n ∈ remove-refsize0(istore) → abs-leb(avol1[n], indexblock(indx, lax, m), mklp(m, m1, lpf, m2)) ∧ m0 = m) ⊦

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Rule argument

fma: lpf0 = LP_FREE

Additional information

Used simplifier rules: ⊦ LP_FREE ≠ LP_INDEX_NODES; (s)%⊦ mklp(m, m0, lpf, m1) = mklp(m2, m3, lpf0, m4) ↔ m = m2 ∧ m0 = m3 ∧ lpf = lpf0 ∧ m1 = m4; (ws)% ⊦ ¬ n ∈ istore → istore[n] = (∅)[n]; (s)% ⊦ n ∈ remove-refsize0(istore) ↔ n ∈ istore ∧ istore[n].ref-size ≠ 0; (ws) Used formulas: lpf0 = LP_FREE