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Proof step 22 from proof abs-istore-cleanup-lpt (previous step)

# avol0 = # avol1, # lpt = # avol1, lpf = LP_INDEX_NODES ↔ n ∈ istore, istore[n] = indexblock(indx0, lax0, m3), remove-refsize0(istore)[n] = indexblock(indx, lax, m), lpt[n] = mklp(m0, m1, lpf, m2), lpf = LP_INDEX_NODES, n < # avol1, n ∈ istore → abs-leb(avol0[n], indexblock(indx0, lax0, m3), mklp(m3, m1, lpf, m2)) ∧ m0 = m3, ∀ n. n < # avol1 ∧ (lpt[n].ref-size ≠ 0 ∨ lpt[n].flags = LP_FREE) → avol0[n] = avol1[n], ¬(n ∈ istore ↔ n ∈ remove-refsize0(istore)) ∨ ¬(n ∈ remove-refsize0(istore) → abs-leb(avol1[n], indexblock(indx, lax, m), mklp(m, m1, lpf, m2)) ∧ m0 = m) ⊦ lpf = LP_FREE, m0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# avol0 = # avol1, # lpt = # avol1, istore[n] = indexblock(indx0, lax0, m3), lpt[n] = mklp(m3, m1, LP_INDEX_NODES, m2), n < # avol1, abs-leb(avol0[n], indexblock(indx0, lax0, m3), mklp(m3, m1, LP_INDEX_NODES, m2)), n ∈ istore, ∀ n. n < # avol1 ∧ (lpt[n].ref-size ≠ 0 ∨ lpt[n].flags = LP_FREE) → avol0[n] = avol1[n] ⊦ m3 = 0, abs-leb(avol1[n], indexblock(indx0, lax0, m3), mklp(m3, m1, LP_INDEX_NODES, m2))

Rule argument

Additional information

Used simplifier rules: ⊦ indexblock(indx, lax, m) = indexblock(indx0, lax0, m0) ↔ indx = indx0 ∧ lax = lax0 ∧ m = m0; (ws)%⊦ n ∈ istore ∧ istore[n].ref-size ≠ 0 → remove-refsize0(istore)[n] = istore[n]; (s)% ⊦ indexblock(indx, lax, m).ref-size = m; (s)% ⊦ n ∈ remove-refsize0(istore) ↔ n ∈ istore ∧ istore[n].ref-size ≠ 0; (ws)% ⊦ LP_FREE ≠ LP_INDEX_NODES; (s)