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Proof step 3 from proof abs-istore-replay-lpt-unchanged (previous step)

# lpt = # avol1, # avol0 = # avol1, ∀ n. n < # avol1 ∧ (n ∈ nx ∨ lpt[n].ref-size ≠ 0 ∨ lpt[n].flags = LP_FREE) → avol0[n] = avol1[n] ⊦ (∀ n. (n < # avol1 ∧ replay-lpt(lpt, nx, # avol1)[n].flags = LP_INDEX_NODES ↔ n ∈ remove-refsize0(istore)) ∧ ( n ∈ remove-refsize0(istore) → abs-leb(avol1[n], remove-refsize0(istore)[n], replay-lpt(lpt, nx, # avol1)[n]) ∧ replay-lpt(lpt, nx, # avol1)[n].ref-size = remove-refsize0(istore)[n].ref-size)) ↔ (∀ n. (n < # avol1 ∧ replay-lpt(lpt, nx, # avol1)[n].flags = LP_INDEX_NODES ↔ n ∈ remove-refsize0(istore)) ∧ ( n ∈ remove-refsize0(istore) → abs-leb(avol0[n], remove-refsize0(istore)[n], replay-lpt(lpt, nx, # avol1)[n]) ∧ replay-lpt(lpt, nx, # avol1)[n].ref-size = remove-refsize0(istore)[n].ref-size))

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information