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Proof step 10 from proof avol-replay-lpt-unchanged-write-right (previous step)

# avol0 = # avol1, # lpt = # avol1, lpt[n0] = mklp(m2, m3, lpf0, m4), lpt[n] = mklp(m, m0, lpf, m1), n < # avol1, n0 < # avol1, ∀ n. n < # avol1 ∧ (n ∈ nx ∨ lpt[n].ref-size ≠ 0 ∨ lpt[n].flags = LP_FREE) → avol0[n] = avol1[n], aleb = avol0[n] ∨ ¬ n ∈ nx ∧ m = 0 ∧ lpf ≠ LP_FREE, n0 ∈ nx ∨ m2 ≠ 0 ∨ lpf0 = LP_FREE ⊦ avol0[n0] = avol1[n, aleb][n0], n0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# lpt = # avol1, # avol0 = # avol1, lpt[n] = mklp(m, m0, lpf, m1), lpt[n0] = mklp(m2, m3, lpf0, m4), n0 < # avol1, n < # avol1, ∀ n. n < # avol1 ∧ (n ∈ nx ∨ lpt[n].ref-size ≠ 0 ∨ lpt[n].flags = LP_FREE) → avol0[n] = avol1[n], n0 ∈ nx ∨ m2 ≠ 0 ∨ lpf0 = LP_FREE, aleb = avol0[n] ∨ ¬ n ∈ nx ∧ m = 0 ∧ lpf ≠ LP_FREE ⊦ avol0[n0] = avol1[n0], n0 = n

Rule argument

Additional information

Used simplifier rules: ⊦ m ≠ n → avol[n, aleb][m] = avol[m]; (s)