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Proof step 2 from proof buf-ro-rw-mode-id-idx (previous step)

id-idx(lpt0, lpt1) ⊦ buf-ro-rw-mode(boolvar, bleb, lpt1, avol) ↔ buf-ro-rw-mode(boolvar, bleb, lpt0, avol)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
id-idx(lpt0, lpt1) ⊦ bleb.isbuf? → bleb.leb < # lpt1 ∧ (boolvar ∧ lpt1[bleb.leb].size = LEB_SIZE ∨ lpt1[bleb.leb].size = # avol[bleb.leb].data) ↔ bleb.isbuf? → bleb.leb < # lpt0 ∧ (boolvar ∧ lpt0[bleb.leb].size = LEB_SIZE ∨ lpt0[bleb.leb].size = # avol[bleb.leb].data)

Rule argument

Additional information

Used simplifier rules: buf-ro-rw-mode: ⊦ buf-ro-rw-mode(boolvar, bleb, lpt, avol) ↔ bleb.isbuf? → bleb.leb < # lpt ∧ ( boolvar ∧ lpt[bleb.leb].size = LEB_SIZE ∨ lpt[bleb.leb].size = # avol[bleb.leb].data);