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Proof step 12 from proof bufs-log-only-id-idx (previous step)

# lpt1 = # lpt0, lpt0[nx.last] = mklp(m6, m7, lpf1, m8), lpt1[nx.last] = mklp(m0, m1, lpf, m2), lpt1[m] = mklp(m3, m4, lpf0, m5), lpt0[m] = mklp(m9, m10, lpf2, m11), m < # lpt0, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ nx ≠ [] ∧ m = nx.last ∧ lpf = LP_GROUP_NODES ∨ lpf0 = LP_INDEX_NODES ↔ nx ≠ [] ∧ m = nx.last ∧ lpf1 = LP_GROUP_NODES ∨ lpf2 = LP_INDEX_NODES

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: m abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ mklp(n2, n3, lpf, m).flags = lpf; (s)% ⊦ mklp(n2, n3, lpf, m).size = n3; (s)% ⊦ mklp(n2, n3, lpf, m).ref-size = n2; (s)%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%⊦ mklp(m, m0, lpf, m1) = mklp(m2, m3, lpf0, m4) ↔ m = m2 ∧ m0 = m3 ∧ lpf = lpf0 ∧ m1 = m4; (ws) Used terms: m