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Proof step 8 from proof freelist-cons-add (previous step)

lpt[n] = mklp(n0, n1, lpf, n2), lpt[n3] = mklp(m, m2, lpf0, m4), n < # lpt, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist ⊦ lpf = LP_FREE, n3 = n, dups(freelist), ¬ n ∈ freelist ∧ (n3 < # lpt ∧ lpf0 = LP_FREE ↔ n3 ∈ freelist)

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 9:
n3 < # lpt ∧ lpt[n3].flags = LP_FREE ↔ n3 ∈ freelist, lpt[n3] = mklp(m, m2, lpf0, m4), lpt[n] = mklp(n0, n1, lpf, n2), n < # lpt, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist ⊦ lpf = LP_FREE, n3 = n, dups(freelist), ¬ n ∈ freelist ∧ (n3 < # lpt ∧ lpf0 = LP_FREE ↔ n3 ∈ freelist)

Rule argument

pos: left 4 terms: n3

Additional information

Used terms: n3