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Proof step 5 from proof freelist-cons-remove-wbufs (previous step)

n < # lpt ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist, lpt.mapIndices(ns, λ lp. lp.size:= LEB_SIZE)[n] = mklp(m, m0, lpf, m1) ⊦ n < # lpt ∧ lpf = LP_FREE ↔ n ∈ freelist, dups(freelist)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
n < # lpt ∧ lpf0 = LP_FREE ↔ n ∈ freelist, lpt.mapIndices(ns, λ lp. lp.size:= LEB_SIZE)[n] = mklp(m, m0, lpf, m1), lpt[n] = mklp(m2, m3, lpf0, m4) ⊦ n < # lpt ∧ lpf = LP_FREE ↔ n ∈ freelist, dups(freelist)

Rule argument

spec: lprops name: elim seq: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1) subst: [lp, m, m0, lpf] → [lpt[n], m1, m2, lpf0]

Additional information

Used simplifier rules: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1); (elim) Used terms: lpt[n], m1, m2, lpf0