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Proof step 11 from proof freelist-cons-write-lpt-other (previous step)

lpt[n, mklp(n0, n1, lpf, n2)][n3] = mklp(m, m3, lpf0, m4), lpt[n] = mklp(m0, m1, lpf, m2), ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist ⊦ n3 < # lpt ∧ lpf0 = LP_FREE ↔ n3 ∈ freelist, n3 = n, dups(freelist)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
lpt[n] = mklp(m0, m1, lpf, m2), lpt[n3] = mklp(m, m3, lpf0, m4), ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist ⊦ n3 < # lpt ∧ lpf0 = LP_FREE ↔ n3 ∈ freelist, n3 = n, dups(freelist)

Rule argument

Additional information

Used simplifier rules: ⊦ m ≠ n → lpt[n, lp][m] = lpt[m]; (s)