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Proof step 8 from proof freelist-cons-write-lpt-other (previous step)

lpt[n] = mklp(m0, m1, lpf0, m2), n < # lpt, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE ↔ n ∈ freelist ⊦ lpf0 = LP_FREE ↔ n ∈ freelist, dups(freelist)

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n

Additional information

Used simplifier rules: ⊦ mklp(n2, n3, lpf, m).flags = lpf; (s) Used terms: n