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Proof step 1 from proof gc-heap-fill-free (conclusion)

⊦ gc-heap(fill(mklparray(n), mklp(n0, n1, LP_FREE, n2)), nx) = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ # gc-heap(fill(mklparray(n), mklp(n0, n1, LP_FREE, n2)), nx, n) = 0, gc-heap(fill(mklparray(n), mklp(n0, n1, LP_FREE, n2)), nx, n) = ∅

Rule argument

Additional information

Used simplifier rules: gc-heap: ⊦ gc-heap(lpt, nx) = gc-heap(lpt, nx, # lpt);%size-zero: ⊦ # gchs ≠ 0 → gchs ≠ ∅; (forward) from specification set-basic[gc-heap-rename-gc-heap-base-keyindex-set]%size-zero-01: ⊦ gchs ≠ ∅ → # gchs ≠ 0; (forward) from specification set-basic[gc-heap-rename-gc-heap-base-keyindex-set]% ⊦ # mklparray(n) = n; (s)% ⊦ # fill(lpt, lp) = # lpt; (s)