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Proof step 2 from proof gc-heap-ididx-h (
previous step
)
id-idx(lpt0, lpt1), m ≤ # lpt1 ⊦ gc-heap(lpt1, nx, m) = gc-heap(lpt0, nx, m)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
id-idx(lpt0, lpt1), m ≤ # lpt1 ⊦ gc-heap(lpt1, nx, m) = gc-heap(lpt0, nx, m)
Rule argument
Additional information