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Proof step 1 from proof id-idx-abs-gstore (conclusion)

⊦ id-idx(lpt0, lpt1) → (abs-gstore(avol, lpt1, gstore, ginval) ↔ abs-gstore(avol, lpt0, gstore, ginval))

System applied rule normalize

And obtained the following new goals

Proof step 2:
id-idx(lpt0, lpt1) ⊦ abs-gstore(avol, lpt1, gstore, ginval) ↔ abs-gstore(avol, lpt0, gstore, ginval)

Rule argument

Additional information