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Proof step 30 from proof id-idx-abs-gstore (previous step)

# lpt1 = # lpt0, lpt1[n] = mklp(m0, m1, lpf, m2), gstore[n] = groupblock(gndx, lax, m), ∀ n. (n < # lpt0 ∧ lpt0[n].flags = LP_GROUP_NODES ↔ n ∈ gstore) ∧ (n ∈ gstore ∧ ¬ n ∈ ginval → abs-leb(avol[n], gstore[n], lpt0[n])) ∧ (n ∈ gstore → lpt0[n].ref-size = gstore[n].ref-size), ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (n < # lpt0 ∧ lpf = LP_GROUP_NODES ↔ n ∈ gstore) ∧ (n ∈ gstore ∧ ¬ n ∈ ginval → abs-leb(avol[n], groupblock(gndx, lax, m), mklp(m0, m1, lpf, m2))) ∧ (n ∈ gstore → m0 = m)

User applied rule all left

And obtained the following new goals

Proof step 31:
# lpt1 = # lpt0, n < # lpt0 ∧ lpt0[n].flags = LP_GROUP_NODES ↔ n ∈ gstore, gstore[n] = groupblock(gndx, lax, m), lpt1[n] = mklp(m0, m1, lpf, m2), n ∈ gstore ∧ ¬ n ∈ ginval → abs-leb(avol[n], gstore[n], lpt0[n]), n ∈ gstore → lpt0[n].ref-size = gstore[n].ref-size, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (n < # lpt0 ∧ lpf = LP_GROUP_NODES ↔ n ∈ gstore) ∧ (n ∈ gstore ∧ ¬ n ∈ ginval → abs-leb(avol[n], groupblock(gndx, lax, m), mklp(m0, m1, lpf, m2))) ∧ (n ∈ gstore → m0 = m)

Rule argument

pos: left 4 terms: n abort: F discard: T computed: T

Additional information

Used terms: n