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Proof step 6 from proof id-idx-abs-gstore (previous step)

# lpt1 = # lpt0, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (∀ n. (n < # lpt0 ∧ lpt1[n].flags = LP_GROUP_NODES ↔ n ∈ gstore) ∧ (n ∈ gstore ∧ ¬ n ∈ ginval → abs-leb(avol[n], gstore[n], lpt1[n])) ∧ (n ∈ gstore → lpt1[n].ref-size = gstore[n].ref-size)) ↔ (∀ n. (n < # lpt0 ∧ lpt0[n].flags = LP_GROUP_NODES ↔ n ∈ gstore) ∧ (n ∈ gstore ∧ ¬ n ∈ ginval → abs-leb(avol[n], gstore[n], lpt0[n])) ∧ (n ∈ gstore → lpt0[n].ref-size = gstore[n].ref-size))

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information