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Proof step 14 from proof id-idx-abs-istore (previous step)

# lpt1 = # lpt0, n < # lpt0 ∧ lpt1[n].flags = LP_INDEX_NODES ↔ n ∈ istore, lpt0[n] = mklp(m0, m1, lpf, m2), istore[n] = indexblock(indx, lax, m), n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, lpt1[n].ref-size), lpt1[n]) ∧ lpt1[n].ref-size = m, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (n < # lpt0 ∧ lpf = LP_INDEX_NODES ↔ n ∈ istore) ∧ (n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, m), mklp(m, m1, lpf, m2)) ∧ m0 = m)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 15:
# lpt1 = # lpt0, n < # lpt0 ∧ lpf0 = LP_INDEX_NODES ↔ n ∈ istore, istore[n] = indexblock(indx, lax, m), lpt0[n] = mklp(m0, m1, lpf, m2), lpt1[n] = mklp(m3, m4, lpf0, m5), n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, m3), lpt1[n]) ∧ m3 = m, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (n < # lpt0 ∧ lpf = LP_INDEX_NODES ↔ n ∈ istore) ∧ (n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, m), mklp(m, m1, lpf, m2)) ∧ m0 = m)

Rule argument

spec: lprops name: elim seq: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1) subst: [lp, m, m0, lpf, m1] → [lpt1[n], m3, m4, lpf0, m5]

Additional information

Used simplifier rules: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1); (elim) Used terms: lpt1[n], m3, m4, lpf0, m5