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Proof step 31 from proof id-idx-abs-istore (previous step)

# lpt1 = # lpt0, n < # lpt0 ∧ lpt0[n].flags = LP_INDEX_NODES ↔ n ∈ istore, lpt1[n] = mklp(m0, m1, lpf, m2), istore[n] = indexblock(indx, lax, m), n ∈ istore → abs-leb(avol[n], istore[n], lpt0[n]) ∧ lpt0[n].ref-size = istore[n].ref-size, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (n < # lpt0 ∧ lpf = LP_INDEX_NODES ↔ n ∈ istore) ∧ (n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, m), mklp(m, m1, lpf, m2)) ∧ m0 = m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
# lpt1 = # lpt0, n < # lpt0 ∧ lpt0[n].flags = LP_INDEX_NODES ↔ n ∈ istore, lpt1[n] = mklp(m0, m1, lpf, m2), istore[n] = indexblock(indx, lax, m), n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, lpt0[n].ref-size), lpt0[n]) ∧ lpt0[n].ref-size = m, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ (n < # lpt0 ∧ lpf = LP_INDEX_NODES ↔ n ∈ istore) ∧ (n ∈ istore → abs-leb(avol[n], indexblock(indx, lax, m), mklp(m, m1, lpf, m2)) ∧ m0 = m)

Rule argument

Additional information

Used simplifier rules: ⊦ indexblock(indx, lax, m).ref-size = m; (s)