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Proof step 11 from proof id-idx-write-both (previous step)

# lpt1 = # lpt0, lpt0[n, mklp(n0, n1, lpf, n2)][n3] = mklp(m, m0, lpf0, m1), lpt1[n, mklp(n0, n1, lpf, m2)][n3] = mklp(m3, m4, lpf1, m5), n3 < # lpt0, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags ⊦ m = m3 ∧ m0 = m4 ∧ lpf0 = lpf1

User applied rule all left

And obtained the following new goals

Proof step 12:
# lpt1 = # lpt0, lpt1[n, mklp(n0, n1, lpf, m2)][n3] = mklp(m3, m4, lpf1, m5), lpt0[n, mklp(n0, n1, lpf, n2)][n3] = mklp(m, m0, lpf0, m1), n3 < # lpt0, n3 < # lpt0 → lpt0[n3].ref-size = lpt1[n3].ref-size ∧ lpt0[n3].size = lpt1[n3].size ∧ lpt0[n3].flags = lpt1[n3].flags ⊦ m = m3 ∧ m0 = m4 ∧ lpf0 = lpf1

Rule argument

pos: left 5 terms: n3 abort: F discard: T computed: T

Additional information

Used terms: n3