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Proof step 2 from proof id-idx-write-both (previous step)

id-idx(lpt0, lpt1) ⊦ id-idx(lpt0[n, mklp(n0, n1, lpf, n2)], lpt1[n, mklp(n0, n1, lpf, m2)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information