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Proof step 2 from proof lpt-free-unref-replay-log (previous step)

lpt-free-unref(lpt) ⊦ lpt-free-unref(replay-log(lpt, nx))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
lpt.mapIndices(elems nx, λ lp. mklp(lp.ref-size, LEB_SIZE, LP_GROUP_NODES, lp.gcheapidx))[n].flags = LP_FREE, n < # lpt, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0 ⊦ lpt.mapIndices(elems nx, λ lp. mklp(lp.ref-size, LEB_SIZE, LP_GROUP_NODES, lp.gcheapidx))[n].ref-size = 0

Rule argument

Additional information

Used simplifier rules: lpt-free-unref: ⊦ lpt-free-unref(lpt) ↔ (∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0);%replay-log: ⊦ replay-log(lpt, nx) = lpt .mapIndices (elems nx, λ lp. mklp(lp.ref-size, LEB_SIZE, LP_GROUP_NODES, lp.gcheapidx) );% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ # lpt.mapIndices(ns, lptfun) = # lpt; (s)