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Proof step 8 from proof lpt-free-unref-replay-log (previous step)

(n ∈ nx ⊃ mklp(lpt[n].ref-size, LEB_SIZE, LP_GROUP_NODES, lpt[n].gcheapidx);lpt[n]) = mklp(m, m0, LP_FREE, m1), n < # lpt, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0 ⊦ m = 0

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 9:
lpt[n] = mklp(m, m0, LP_FREE, m1), n < # lpt, ∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0 ⊦ m = 0, n ∈ nx

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ mklp(m, m0, lpf, m1) = mklp(m2, m3, lpf0, m4) ↔ m = m2 ∧ m0 = m3 ∧ lpf = lpf0 ∧ m1 = m4; (ws)% ⊦ LP_FREE ≠ LP_GROUP_NODES; (s)