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Proof step 2 from proof lpt-free-unref-replay-lpt (previous step)

n ≤ # lpt ⊦ (∀ n0. n0 < # lpt ∧ replay-lpt(lpt, nx, n)[n0].flags = LP_FREE → replay-lpt(lpt, nx, n)[n0].ref-size = 0) ↔ (∀ n. n < # lpt ∧ lpt[n].flags = LP_FREE → lpt[n].ref-size = 0)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information