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Proof step 22 from proof lpt-free-unref-replay-lpt (previous step)

(lpf = LP_INDEX_NODES ∧ m2 ≠ 0 ⊃ mklp(m2, LEB_SIZE, LP_INDEX_NODES, m4);(m2 = 0 ⊃ mklp(0, 0, LP_FREE, m4);mklp(m2, m3, lpf, m4))) = mklp(m, m0, LP_FREE, m1), lpt[n0] = mklp(m2, m3, lpf, m4), n0 < # lpt, n0 < n, n ≤ # lpt ⊦ lpf = LP_FREE, m = 0, n0 ∈ nx

Heuristic if-then-else split applied rule case distinction

And closed the goal!

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ mklp(m, m0, lpf, m1) = mklp(m2, m3, lpf0, m4) ↔ m = m2 ∧ m0 = m3 ∧ lpf = lpf0 ∧ m1 = m4; (ws)