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Proof step 11 from proof lpt-leb-size-cleanup (previous step)

(m2 = 0 ∧ lpf0 ≠ LP_FREE ⊃ mklp(0, 0, LP_FREE, m4);mklp(m2, m3, lpf0, m4)) = mklp(m, m0, lpf, m1), lpt[n] = mklp(m2, m3, lpf0, m4), m2 = 0, n < # lpt, LEB_SIZE < m0, m3 < m0, m3 ≤ LEB_SIZE, ∀ n. n < # lpt → lpt[n].size ≤ LEB_SIZE ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
(lpf0 ≠ LP_FREE ⊃ mklp(0, 0, LP_FREE, m4);mklp(0, m3, LP_FREE, m4)) = mklp(m, m0, lpf, m1), lpt[n] = mklp(0, m3, lpf0, m4), m3 < m0, LEB_SIZE < m0, n < # lpt, m3 ≤ LEB_SIZE, ∀ n. n < # lpt → lpt[n].size ≤ LEB_SIZE ⊦

Proof step 11 from proof lpt-leb-size-cleanup (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information