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Proof step 18 from proof lpt-leb-size-id-idx (previous step)

# lpt1 = # lpt0, lpt1[n] = mklp(m, m0, lpf, m1), lpt0[n] = mklp(m, m0, lpf, m2), LEB_SIZE < m0, n < # lpt0, ∀ n. n < # lpt0 → lpt0[n].size ≤ LEB_SIZE ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n abort: F discard: T computed: T

Additional information

Used simplifier rules: fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ mklp(n2, n3, lpf, m).size = n3; (s)% ⊦ ¬ n < n; (s) Used terms: n