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Proof step 3 from proof lpt-ram-flash-allocate (previous step)

# lpt0 = # lpt1, lpt1[n0].flags = LP_GROUP_NODES, lpt0[n0].flags = LP_GROUP_NODES, n0 < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES ∧ ¬ n ∈ nx → lpt1[n].size = lpt0[n].size ⊦ lpt1[n0].size = lpt0[n0].size, n0 = n, n0 ∈ nx

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
# lpt0 = # lpt1, lpt0[n0].flags = LP_GROUP_NODES, lpt1[n0] = mklp(m, m0, lpf, m1), lpf = LP_GROUP_NODES, n0 < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES ∧ ¬ n ∈ nx → lpt1[n].size = lpt0[n].size ⊦ m0 = lpt0[n0].size, n0 = n, n0 ∈ nx

Rule argument

spec: lprops name: elim seq: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1) subst: [lp, m, m0, lpf, m1] → [lpt1[n0], m, m0, lpf, m1]

Additional information

Used simplifier rules: ⊦ ((m = lp.ref-size ∧ m0 = lp.size) ∧ lpf = lp.flags) ∧ m1 = lp.gcheapidx ↔ lp = mklp(m, m0, lpf, m1); (elim) Used terms: lpt1[n0], m, m0, lpf, m1