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Proof step 7 from proof lpt-ram-flash-allocate (previous step)

# lpt0 = # lpt1, lpt0[n0] = mklp(m2, m3, LP_GROUP_NODES, m4), lpt1[n0] = mklp(m, m0, LP_GROUP_NODES, m1), n0 < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES ∧ ¬ n ∈ nx → lpt1[n].size = lpt0[n].size ⊦ m0 = m3, n0 = n, n0 ∈ nx

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0 abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ mklp(n2, n3, lpf, m).flags = lpf; (s)% ⊦ mklp(n2, n3, lpf, m).size = n3; (s) Used terms: n0