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Proof step 11 from proof lpt-ram-flash-cleanup (previous step)

# lpt0 = # lpt1, (m5 = 0 ∧ lpf ≠ LP_FREE ⊃ mklp(0, 0, LP_FREE, m7);lpt1[n]) = mklp(m, m0, LP_GROUP_NODES, m1), lpt0[n] = mklp(m2, m3, LP_GROUP_NODES, m4), lpt1[n] = mklp(m5, m6, lpf, m7), n < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES → lpt1[n].size = lpt0[n].size ⊦ m0 = m3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
# lpt0 = # lpt1, (m5 = 0 ∧ lpf ≠ LP_FREE ⊃ mklp(0, 0, LP_FREE, m7);mklp(m5, m6, lpf, m7)) = mklp(m, m0, LP_GROUP_NODES, m1), lpt1[n] = mklp(m5, m6, lpf, m7), lpt0[n] = mklp(m2, m3, LP_GROUP_NODES, m4), n < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES → lpt1[n].size = lpt0[n].size ⊦ m0 = m3

Proof step 11 from proof lpt-ram-flash-cleanup (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information