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Proof step 13 from proof lpt-ram-flash-cleanup (previous step)

# lpt0 = # lpt1, lpt0[n] = mklp(m2, m3, LP_GROUP_NODES, m4), lpt1[n] = mklp(m5, m6, lpf, m7), mklp(m5, m6, lpf, m7) = mklp(m, m0, LP_GROUP_NODES, m1), n < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES → lpt1[n].size = lpt0[n].size, m5 ≠ 0 ∨ lpf = LP_FREE ⊦ m0 = m3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
# lpt0 = # lpt1, lpt0[n] = mklp(m2, m3, LP_GROUP_NODES, m4), lpt1[n] = mklp(m5, m0, LP_GROUP_NODES, m7), n < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES → lpt1[n].size = lpt0[n].size ⊦ m0 = m3, m5 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ LP_FREE ≠ LP_GROUP_NODES; (s)%⊦ mklp(m, m0, lpf, m1) = mklp(m2, m3, lpf0, m4) ↔ m = m2 ∧ m0 = m3 ∧ lpf = lpf0 ∧ m1 = m4; (ws)