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Proof step 9 from proof lpt-ram-flash-cleanup (previous step)

# lpt0 = # lpt1, (n < # lpt1 ⊃ (lpt1[n].ref-size = 0 ∧ lpt1[n].flags ≠ LP_FREE ⊃ mklp(0, 0, LP_FREE, lpt1[n].gcheapidx);lpt1[n]);lpt1[n]) = mklp(m, m0, LP_GROUP_NODES, m1), lpt0[n] = mklp(m2, m3, LP_GROUP_NODES, m4), n < # lpt1, ∀ n. n < # lpt1 ∧ lpt0[n].flags = LP_GROUP_NODES ∧ lpt1[n].flags = LP_GROUP_NODES → lpt1[n].size = lpt0[n].size ⊦ m0 = m3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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