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Proof step 22 from proof lpt-ram-flash-id-idx (previous step)

# lpt = # lpt0, # lpt1 = # lpt0, lpt[n] = mklp(m2, m3, LP_GROUP_NODES, m4), lpt1[n] = mklp(m, m0, LP_GROUP_NODES, m1), n < # lpt0, ∀ n. n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags, ∀ n. n < # lpt0 ∧ lpt[n].flags = LP_GROUP_NODES ∧ lpt0[n].flags = LP_GROUP_NODES ∧ ¬ n ∈ nx → lpt0[n].size = lpt[n].size ⊦ m0 = m3, n ∈ nx

User applied rule all left

And obtained the following new goals

Proof step 23:
# lpt1 = # lpt0, # lpt = # lpt0, lpt1[n] = mklp(m, m0, LP_GROUP_NODES, m1), lpt[n] = mklp(m2, m3, LP_GROUP_NODES, m4), n < # lpt0, n < # lpt0 → lpt0[n].ref-size = lpt1[n].ref-size ∧ lpt0[n].size = lpt1[n].size ∧ lpt0[n].flags = lpt1[n].flags, ∀ n. n < # lpt0 ∧ lpt[n].flags = LP_GROUP_NODES ∧ lpt0[n].flags = LP_GROUP_NODES ∧ ¬ n ∈ nx → lpt0[n].size = lpt[n].size ⊦ m0 = m3, n ∈ nx

Rule argument

pos: left 6 terms: n abort: F discard: T computed: T

Additional information

Used terms: n