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Proof step 2 from proof replay-lpt-at-above (previous step)

m < # lpt, n ≤ m ⊦ replay-lpt(lpt, nx, n)[m] = lpt[m]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n < # lpt, m < # lpt, n ≤ m ⊦ replay-lpt(lpt, nx, n)[m] = lpt[m]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic